[racket] regexp-replace* with input-port ==> Re: multi-replace function
Two minutes ago, YC wrote:
> This brings up something I noticed earlier today looking at regexp
> docs: regexp-replace family does not work with input-port, when the
> other regexp-* functions do.
>
> Are there reasons for the difference? Is it because input-port cannot be
> written to?
Well, that would be an obvious issue... It might be possible to do
this if they're extended to get an output port too, something like:
(regexp-replace* #rx"foo" inp "bar" outp)
doing the same thing as the loop that I wrote.
> But since the string & bytes variants all generate new output, that
> will seem to be the same for input-port source anyways.
(I didn't follow that.)
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((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay:
http://barzilay.org/ Maze is Life!