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[racket] (floor (/ ....))

From: Laurent (laurent.orseau at gmail.com)
Date: Tue Jun 11 04:17:04 EDT 2013		 
On Tue, Jun 11, 2013 at 9:45 AM, Stephan Houben <stephanh42 at gmail.com>wrote:

>   replace (floor (/ a b)) with (modulo a b)
>


Actually:
> (modulo 10 3)
1
> (remainder 10 3)
1
> (quotient 10 3)
3
> (floor (/ 10 3))
3

`modulo' is more like `remainder', except for negative numbers.

Laurent
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