[racket] Cube

From: Ashley Fowler (afowler2 at broncos.uncfsu.edu)
Date: Thu Sep 13 13:22:09 EDT 2012

I have to write a procedure (cube-two X Y) that takes two numeric arguments
and returns a list of their cubes.

So far I have...

(define cube(lambda(x)(* x x x)))...which takes ONE numeric arguments...example below...

(cube 3) ==> ( 27)

How could I make it to take two numeric arguments?

For instance...

(cube-two 1 4)  ==> (1  64)
(cube-two 2 5)  ==> (8  125)

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