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<p>I have to write a procedure (cube-two X Y) that takes two numeric arguments <br>
and returns a list of their cubes.</p>
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<p>So far I have...</p>
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<p>(define cube(lambda(x)(* x x x)))...which takes ONE numeric arguments...example below...</p>
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<p>(cube 3) ==> ( 27)</p>
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<p>How could I make it to take two numeric arguments?</p>
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<p>For instance...</p>
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<p>(cube-two 1 4) ==> (1 64)<br>
(cube-two 2 5) ==> (8 125)<br>
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