[racket] ... in macro defining macros?
I think its explained here
http://docs.racket-lang.org/reference/stx-patterns.html?q=ellipses#(form._((lib._racket/private/stxcase-scheme..rkt)._syntax)) <http://docs.racket-lang.org/reference/stx-patterns.html?q=ellipses#%28form._%28%28lib._racket/private/stxcase-scheme..rkt%29._syntax%29%29>
at (ellipses stat-template), although I find the explanation confusing. Probably an example of (... ...) would be useful there.
On 08/03/2012 09:51 PM, Nick Sivo wrote:
> Hi Jon,
>
> Thanks, that works perfectly!
>
> Did I miss that somewhere in the documentation? I don't recall seeing
> an example of it.
>
> Best,
> Nick
>
> On Thu, Aug 2, 2012 at 11:55 PM, Jon Rafkind <rafkind at cs.utah.edu> wrote:
>> To match a literal ellipses in syntax-parse use #:literal [(ellipses ...)] and match on the term `ellipses', then to use a literal ellipses in the template use (... ...) instead of just ...
>>
>> It looks like you only want the latter, so
>>
>> (define-syntax (example stx)
>> (syntax-parse stx
>> [(_ name:id) #'(define-syntax (name stx)
>> (syntax-parse stx
>> [(_ args (... ...)) #'(args (... ...)))])]))
>>
>> On 08/02/2012 11:30 PM, Nick Sivo wrote:
>>> Hi,
>>>
>>> I'm trying to use ... in the inner macro of a macro defining macro,
>>> but can't figure out the right way to escape it.
>>>
>>> Here's a minimal (pointless) example:
>>>
>>> (require (for-syntax syntax/parse))
>>>
>>> (define-syntax (example stx)
>>> (syntax-parse
>>> stx
>>> ;#:literals (...) ; Doesn't help :(
>>> [(_ name:id)
>>> #'(define-syntax (name stx)
>>> (syntax-parse
>>> stx
>>> [(_ args ...) #'(args ...)]))]))
>>>
>>> The goal is to have (example invisible) define a macro called
>>> invisible that erases itself.
>>>
>>> Any ideas? The full code I'm trying to enable follows below if you'd
>>> like more context.
>>>
>>> Thanks,
>>> Nick
>>>
>>> #lang racket
>>>
>>> (require (for-syntax syntax/parse)
>>> racket/splicing)
>>>
>>> ;;;
>>> ;;; Procedure Application
>>> ;;;
>>>
>>> (define arc-nil #f)
>>>
>>> (define-syntax (arc-#%app stx)
>>> (syntax-parse
>>> stx
>>> [(_ fn:expr arg:expr)
>>> #'(let ([efn fn])
>>> (cond [(procedure? efn) (#%app efn arg)]
>>> [(pair? efn) (#%app list-ref efn arg)]
>>> [(string? efn) (#%app string-ref efn arg)]
>>> [(hash? efn) (#%app hash-ref efn arg arc-nil)]
>>> [else (#%app efn arg)]))]
>>> [(_ fn:expr arg1:expr arg2:expr)
>>> #'(let ([efn fn])
>>> (if (hash? efn)
>>> ; Have to use the lamda in case arg2 is a function
>>> ; See hash-ref docs for more info
>>> (#%app hash-ref fn arg1 (lambda () arg2))
>>> (#%app fn arg1 arg2)))]
>>> [(_ args ...)
>>> #'(#%app args ...)]))
>>>
>>> ; This allows cross module mutation of globals
>>> (define-syntax (declare-with-set-transformer stx)
>>> (syntax-parse
>>> stx
>>> ;#:literals (...) ; Doesn't help :(
>>> [(_ var:id)
>>> #'(declare-with-set-transformer var (gensym 'unintialized))]
>>> [(_ var:id init-val:expr)
>>> (let ([store-name (gensym (syntax->datum #'var))])
>>> #`(begin
>>> (define #,store-name init-val)
>>> (splicing-let ([set (lambda (val)
>>> (set! #,store-name val))])
>>> (define-syntax var
>>> (make-set!-transformer
>>> (lambda (stx)
>>> (syntax-case stx (set!)
>>> [(set! id val) #'(set val)]
>>> ; Uses Racket's #%app, which doesn't work for arc
>>> [(id . args) #'(#,store-name . args)] ; function application
>>> ; Obviously invalid syntax
>>> ;[(id . args) #'(arc-#%app #,store-name . args)]
>>> ; Errors because ... isn't recognized as a literal
>>> ;[(id args ...) #'(arc-#%app #,store-name args ...)]
>>> [id (identifier? #'id) #'#,store-name])))))))]))
>>>
>>> ; Demo of what I'm looking for
>>> (define test (make-hash))
>>> (hash-set! test 'key 'value)
>>> (displayln (arc-#%app test 'key))
>>>
>>> ; Example of what doesn't work right now
>>> (declare-with-set-transformer test2 (make-hash))
>>> (hash-set! test2 'key 'value)
>>> (displayln (test2 'key))
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