[racket] Lazy take is the identity?

> P.S. I was surprised to see that list-ref in #lang lazy takes the args in
> opposite order than in #lang racket (which takes the list first).

I'm seeing the same behavior:

Welcome to DrRacket, version 5.0.99.6 [3m].
Language: Lazy Racket [custom].
> (list-ref '(1 2 3) 1)
2
> (list-ref 1 '(1 2 3))
. . C:\plt\collects\lazy\lazy.rkt:43:24: list-ref: expects type
<non-negative exact integer> as 2nd argument, given: (1 2 3); other
arguments were: 1




On Wed, Jan 26, 2011 at 3:40 AM, Mark Engelberg
<mark.engelberg at gmail.com> wrote:
> I get an error in 5.0.2, rather than 0.
>
> --Mark
>
> P.S. I was surprised to see that list-ref in #lang lazy takes the args in
> opposite order than in #lang racket (which takes the list first).
>
> On Tue, Jan 25, 2011 at 11:27 PM, John Clements <clements at brinckerhoff.org>
> wrote:
>>
>> I would expect this program to signal an error:
>>
>> #lang lazy
>>
>> (define zeros (cons 0 zeros))
>>
>> (define should-be-error (list-ref (take 15 zeros) 1324))
>>
>>
>> ... but instead should-be-error is bound to zero.  How can I take the
>> 1000th element of a list with only 15 elements?  I'm tempted to make snide
>> comments about laziness, but I'm sure it'll backfire when it turns out that
>> somehow that's the right answer after all.
>>
>> Bug report?
>>
>> John
>>
>>
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