[racket] Printing multiple stmts in cond

Ok. Here's what I am trying to do.

I am parsing incoming racket code and generating back racket code.

In my case, I have an incoming function which takes 4 arguments and I need
to generate a function which takes in 5 args when a condition satisfies, if
not then the original 4 args .

Something like,

Input-->
(f x1 x2 x3 x4)

Output-->
(FF x1 x2 xNEW x3 x4)

--------------------------------------------------

(define (parse-func exp)
   (cond
............

   [(f? exp)
       `(FF
         ,x1
         ,x2
         ,(if (condition?)
              xNEW)

         ,x3
         ,x4)]

(The above is just pseudo-code) As shown above, when the if condition fails
I just want 4 args. But a default #<void> is passed instead when used with
cond.

I am new to racket and functional programing in general, so I am not able to
express my problem very accurately :(
Hope the above example is clear enough to explain what I am doing.



On Sat, Apr 30, 2011 at 7:00 AM, Neil Van Dyke <neil at neilvandyke.org> wrote:

> nikhil wrote at 04/30/2011 02:52 AM:
>
>  Basically, I dont want to execute an else stmt or return multiple values.
>> I just want to return "stmt1" if condition satisfies and dont do anything if
>> false. No returning #<void> or anything.
>>
>
> An expression always produces at least one value, even if the value is the
> void value.  (Usually, a REPL will hide a returned void value from you, but
> a void value is still being returned, which can be confusing.)
>
> If you can show *why* you don't want to produce *any* value, then people
> can show you different ways to write that code.
>
> --
> http://www.neilvandyke.org/
>
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