[racket] Rookie Question on Functional Languages

Ryan said it all. But since I decided to check on the long-forgotten do loops, I thought I'd show you the one-liner: 

> (do ([x 10 (- x 1)]) ((zero? x)) (displayln x))
10
9
8
7
6
5
4
3
2
1

Loops are ugly -- Matthias




On Dec 9, 2010, at 1:51 PM, Luke Jordan wrote:

> Here's a rookie question that stems from HtDP 29.3.2.
> 
> The idea is to test an expression a number of times while timing it and compare to another version of the same function.  The expression finds a route in a vector (graph) from node 0 to node 4.  The way I would do this in C/Python is with a while loop, while the counter is not zero execute the expression (ignore return value), and wrap it in the timer.  In Racket I came up with:
> 
> (time (for-each
>        (lambda (dest) (find-route 0 dest Graph))
>        (make-list 1000 4)))
> 
> It seems unnecessarily tricky, but I couldn't think of a better way.  Am I missing a piece?  Does it only seem tricky because Racket is my first functional language.
> 
> aTdHvAaNnKcSe
> 
> ^ actually unnecessarily tricky
> 
> Luke
> 
> 
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