From: Dave Herman (dherman at ccs.neu.edu) Date: Sat Oct 1 14:34:27 EDT 2005 |
|
Can we assume that: (symbol? (string->symbol ":a")) ; => #t (symbol? '|:a|) ; => #t (lambda (|:a|) |:a|) ; => #<procedure> will still hold? Dave
Posted on the users mailing list. |
|