[plt-scheme] HtDP newbie question, 12.4.2
Okay you have gotten to the point where you're jumping even faster.
Slogan:
furiously fast programming leads to nowhere.
;; ---
All I was getting at is a simple point:
Your recursive calls in insert-everywhere/one-word produced almost
all the work in the recursion. Indeed, it always produces all but one
word, except that the first letter from the original word is missing.
Example:
given: the recursion in the
final result I want plus
'X "ATE" "X" "TE" --> "XTE" "TXE" "TEX" "AXTE" "ATXE"
"ATXE" "ATEX" "XATE"
Given the recursive result (the list of words that are too short by
the first letter in the orginal word) can you design a function that
adds this letter (no matter what it is) to the front of all these
words you have gotten back?
DONE?
After that: what is missing?
-- Matthias
On Mar 28, 2008, at 11:51 AM, Cooke Kelsey wrote:
> OK, that helps me a little. If I insert "cons (first word)," then
> I can rebuild the word:
>
> (define (cons-function word)
> (cond
> [(empty? (rest word)) word]
> [else (cons (first word) (cons-function (rest word)))]))
>
> (cons-function (list 'A 'T 'W)) = (list 'A 'T 'W)
>
> The problem is how to add this to a shrinking function:
>
> (define (shrinking-function s word)
> (cond
> [(empty? (rest word)) empty]
> [else (list (append (list s) word) (shrinking-function s (rest
> word)))]))
> (This shrinking function isn't exactly what I want, but at least it
> gives me (list 'X 'A 'T 'W) and (list 'X 'T 'W)).
>
> So I append them together:
>
> (append (cons-function (list 'A 'T 'W)) (shrinking-function 'X
> (list 'A 'T 'W)))
>
> And I get this:
>
> (list (list 'X 'A 'T 'W) (list (list 'X 'T 'W) empty)) (list 'A 'T
> 'W (list 'X 'A 'T 'W) (list (list 'X 'T 'W) empty))
>
> Garbage!
>
> As a last resort, I try to combine cons and shrinking functions
> together:
>
> (define (cons+shrinking-function s word)
> (cond
> [(empty? (rest word)) word]
> [else (append (cons (first word) (cons+shrinking-function 'X
> (rest word))) (list s) (rest word))]))
>
> (cons+shrinking-function 'X (list 'A 'T 'W)) = (list 'A 'T 'W 'X 'W
> 'X 'T 'W)
>
> It looks kind of nice, but it is even further from the expected
> result.
>
>
> Matthias Felleisen <matthias at ccs.neu.edu> wrote:
>
> How about (cons 'A (list 'X 'T)) = (list 'A 'X 'T)
>
>
>
>
> On Mar 28, 2008, at 10:53 AM, Cooke Kelsey wrote:
>> (append (list 'A) (list 'X 'T)) = (list 'A 'X 'T)
>>
>> Matthias Felleisen <matthias at ccs.neu.edu> wrote:
>>
>> Here is a definition of 'adding in the missing element':
>>
>> * If a list X misses the symbol 'A (at the front), how do you get
>> a list that has the 'A and all of X?
>>
>> * X = (list 'X 'T) and 'A --> I want (list 'A 'X 'T). How do I do
>> that?
>>
>> -- Matthias
>>
>>
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>> Try it now.
>
>
>
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