Thanks Danny, that does the trick nicely. Cheers, Kieron. <div class="gmail_quote">On Mon, Sep 10, 2012 at 2:00 PM, Danny Yoo <<a href="mailto:dyoo@hashcollision.org" target="_blank">dyoo@hashcollision.org</a>> wrote: <blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div class="im">> I see the function read-icos in file/ico, and also the function ico->argb > which gives a bytes? that represents an argb image, but I can't figure out > how to get from a bytes? to an actual argb?. </div>Hi Kieron, An argb has a vector that we can probably mutate. It also holds width and height, so we need to preserve those too... Hmm. Something VERY strange is happening with the alphas being produced by ico->argb vs the alphas expected by the bitmap functions. They seem... flipped! Here's source that should do the trick for you, but I'm confused about what's going on with the alpha transparency stuff: ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; #lang racket/base (require file/ico) (require mrlib/cache-image-snip) (define (ico->bitmap x) (define argb-bytes (ico->argb x)) (argb->bitmap (make-argb (for/vector ([b argb-bytes] [i (in-naturals)]) (if (= (remainder i 4) 0) (- 255 b) b)) (ico-width x) (ico-height x)))) ;; For example ;;(map (lambda (x) (ico->bitmap x)) ;; (read-icos "001_01.ico")) ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; Good luck! </blockquote></div>