You should look into the composing image functions available. The beside function should make it so you don't need to calculate exactly where the cursor should be displayed. <div class="gmail_quote">On Thu, Apr 5, 2012 at 11:39 AM, Roelof Wobben <<a href="mailto:r.wobben@home.nl">r.wobben@home.nl</a>> wrote: <blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">Op 5-4-2012 19:28, Danny Yoo schreef:<div class="im"> <blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"> <a href="http://www.ccs.neu.edu/home/matthias/HtDP2e/htdp2e-part1.html#(part._edit1)" target="_blank">http://www.ccs.neu.edu/home/matthias/HtDP2e/htdp2e-part1.html#(part._edit1)</a> We need more context because there's not enough information in the question to tell what you're trying to do yet. Good luck! </blockquote> Yes, I mean that exercise. </blockquote> Ah. Ok. Can you get the position where the cursor should start by taking the image for the left side text, and take its width? </blockquote> </div> Yes, I could. Where I see a problem is here : I start with this : aaaaa| now someone press 3 times the left key. So I have aa/aaa How can I know where the cursor is now. Or can I do width - 3 times 11 ? Roelof<div class="HOEnZb"><div class="h5"> ____________________ Racket Users list: <a href="http://lists.racket-lang.org/users" target="_blank">http://lists.racket-lang.org/users</a> </div></div></blockquote></div>