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<DIV><FONT face="Courier New" size=2>Lately I have played with redex. It is very
nice. </FONT><FONT face="Courier New" size=2>Although redex can be used for a
bigger set of languages, I played with lambda calculus only, making procedures
such as to find normal forms (if possible within a reasonable amount of steps),
checking equality of terms modulo alpha congruence, currying of uncurried
shorthand, and a predicate for equality of lambda terms (reflexive and
transitive and symmetrized closure of beta and eta reduction) </FONT><FONT
face="Courier New" size=2>The last predicate is incomplete of course and I have
made it to halt if no answer can be found within a reasonable number of steps. I
have the pleasure to share my code with you. You can download it
from:</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2><A
href="">http://www.telefonica.net/web2/koot/rdx.scm</A></FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2>Thanks to Robby Findler and the PLT
team.</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2>Would it be possible to add a
in-left-most-hole to the reduction rules of redex? (same as in-hole, but
applying to the leftmost one only) May be I should try to add iyt
myself?</FONT></DIV>
<DIV><FONT face="Courier New" size=2>Jos</FONT></DIV></FONT></DIV></BODY></HTML>