<html><body style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space; "> <div><br></div><div>How about (cons 'A (list 'X 'T)) = (list 'A 'X 'T)</div><div><br></div><div><br></div><div><br></div><br><div><html>On Mar 28, 2008, at 10:53 AM, Cooke Kelsey wrote:</html><br class="Apple-interchange-newline"><blockquote type="cite">(append (list 'A) (list 'X 'T)) = (list 'A 'X 'T)<br><br><b><i>Matthias Felleisen <<a href="mailto:matthias@ccs.neu.edu">matthias@ccs.neu.edu</a>></i></b> wrote: <blockquote class="replbq" style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #1010ff 2px solid"> <div><br></div> <div>Here is a definition of 'adding in the missing element': </div> <div><br></div> <div>* If a list X misses the symbol 'A (at the front), how do you get a list that has the 'A and all of X? </div> <div><br></div> <div>* X = (list 'X 'T) and 'A --> I want (list 'A 'X 'T). How do I do that? </div> <div><br></div> <div>-- Matthias</div> <div><br></div></blockquote><div> <br class="khtml-block-placeholder"></div><hr size="1">Be a better friend, newshound, and know-it-all with Yahoo! Mobile. <a href="http://us.rd.yahoo.com/evt=51733/*http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ "> Try it now.</a></blockquote></div><br></body></html>