[racket] Calculating cumulative sum of the list
Add memoization to fix that
(define (memo f)
(let ([cache (make-hash)])
(lambda xs
(hash-ref! cache xs (thunk (apply f xs))))))
(define (cumulative-sum xs)
(map (memo (curry foldl + 0))
(build-list (length xs)
(compose (curry take xs)
add1))))
On Thu, Jan 22, 2015 at 11:21 AM, Matthias Felleisen <matthias at ccs.neu.edu>
wrote:
>
> Consider the performance implications.
>
>
> On Jan 22, 2015, at 1:59 PM, Jack Firth <jackhfirth at gmail.com> wrote:
>
> > If you're using all of racket, here's a way to do it with heavy usage of
> higher order functions
> >
> > #lang racket
> >
> > (define (cumulative-sum xs)
> > (map (curry foldl + 0)
> > (build-list (length xs)
> > (compose (curry take xs)
> > add1))))
> >
> > On Thu, Jan 22, 2015 at 6:34 AM, Matthias Felleisen <
> matthias at ccs.neu.edu> wrote:
> >
> > #lang racket
> >
> > ;; [Listof Number] -> [Listof Number]
> > ;; given (a b c ...) produce (a (+ a b) (+ a b c) ...)
> > (define (cumulative-sum l #;"final private:" [so-far 0])
> > (cond
> > [(empty? l) '()]
> > [else (define next (+ so-far (first l)))
> > (cons next (cumulative-sum (rest l) next))]))
> >
> > (module+ main
> > (cumulative-sum '(1 2 3)))
> >
> > ;; The comments are HtDP-style, but the optional entry parameter is not
> available in the teaching languages.
> >
> >
> > On Jan 22, 2015, at 8:53 AM, Alexandr M <rus314 at gmail.com> wrote:
> >
> > > Hello,
> > >
> > > I am trying to replicate functionality of this code in Python:
> > >
> > > https://gist.github.com/m-blog/22b7c5d31b3839ffba50#file-cumsum-py
> > >
> > > in Racket without usage of any libraries.
> > >
> > > What would the most optimal / concise way to do it in Racket?
> > >
> > > Thank you.
> > >
> > > --
> > > Best regards,
> > > Alex
> > > ____________________
> > > Racket Users list:
> > > http://lists.racket-lang.org/users
> >
> >
> > ____________________
> > Racket Users list:
> > http://lists.racket-lang.org/users
> >
>
>
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