[racket] integer-sqrt

The docs, I believe.

Robby

On Fri, Sep 12, 2014 at 5:21 PM, Patrick Useldinger
<uselpa.list at gmail.com> wrote:
> Hi all,
>
> according to the documentation, the above procedure accepts a *number* and
> returns an integer.
>
> But (at least in Racket 6.1) there's an error message stating that the
> parameter needs to be an *integer*:
>
> ---------------------------------------
>  > (integer-sqrt 151.29)
>   integer-sqrt: contract violation
>   expected: integer?
>   given: 151.29
> ---------------------------------------
>
> Is this an error in the documentation or in the implementation?
>
> Regards,
> -Patrick
> ____________________
>  Racket Users list:
>  http://lists.racket-lang.org/users