[racket] Strange macro behavior with set! and syntax-local-introduce
Did you want this:
#lang racket
(require (for-syntax syntax/parse racket/syntax))
(define-for-syntax funny #f)
(define-syntax (make-funny-set! stx)
(syntax-parse stx
[(_ v) #`(define #,(begin (set! funny (format-id stx "g")) funny) v)]))
(define-syntax (funny-ref stx)
(syntax-parse stx
[(_) funny]))
(define-syntax (funny-set! stx)
(syntax-parse stx
[(_ v) #`(set! #,funny v)]))
(make-funny-set! 2)
(void (void (void (funny-set! 3))))
(funny-ref)
[I had to write such a macro a while back, and the above is roughly what I remember doing. Note the lexical context]
On May 15, 2014, at 5:25 PM, Spencer Florence <spencer at florence.io> wrote:
> I'm attempting to write a macro which introduces a new id, then another macro that set!s that id.
> Example:
>
> #lang racket
> (require (for-syntax syntax/parse racket/syntax))
> (define-for-syntax funny #f)
> (define-syntax (make-funny-set! stx)
> (syntax-parse stx
> [(_ v)
> (define unmarked (generate-temporary))
> (set! funny (syntax-local-introduce unmarked))
> #`(define #,unmarked v)]))
> (define-syntax (funny-ref stx)
> (syntax-parse stx
> [(_)
> funny]))
> (define-syntax (funny-set! stx)
> (syntax-parse stx
> [(_ v)
> #`(set! #,(syntax-local-introduce funny) v)]))
>
> (make-funny-set! 2)
> (funny-set! 3)
> (funny-ref)
>
> This program works as I expect, evaluating to 3. However if I change (funny-set! 3) to (void (funny-set! 3)) I get the error: "set!: unbound identifier in module in: g1"
>
> I do not get this error if I change (funny-ref) to (void (funny-ref)).
>
> If I look at the expansion of the (void (funny-set! 3)) program in drracket's macro stepper the the g1 in (define g1 2) and the g1 in (void (set! g1 3)) have the same color.
>
> To keep on with the strange, if I change the #,(syntax-local-introduce funny) inside of funny-set! to #,funny inside the behavior of all programs remains the same.
>
> Could someone explain whats going on?
>
> --Spencer
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