[racket] Contract for function with vararg

Why isn't:

  (->* (input-port? any/c) #:rest list? any)

by itself the contract that you want?

Robby


On Sun, Jun 29, 2014 at 12:08 PM, Alexander D. Knauth
<alexander at knauth.org> wrote:
> You can use or/c to do this, as long as you guard them like this so that no
> more than one contract matches at a time:
> (or/c
>  (and/c (procedure-has-arity/c 2) (-> input-port? any/c any))
>  (and/c (procedure-has-arity/c 3) (-> input-port? any/c any/c any))
>  (and/c (procedure-has-arity/c 4) (-> input-port? any/c any/c any/c any))
>  (->* (input-port? any/c) #:rest list? any)
>  )
>
> Or, you could use if/c from unstable/contract, or define a cond/c macro like
> this:
> (require unstable/contract)
> (define-syntax cond/c
>   (syntax-rules (else)
>     [(cond/c) none/c]
>     [(cond/c [else else-c])
>      else-c]
>     [(cond/c [pred then-c] clause ...)
>      (if/c pred
>            then-c
>            (cond/c clause ...))]))
>
> (cond/c [(procedure-has-arity/c 2) (-> input-port? any/c any)]
>         [(procedure-has-arity/c 3) (-> input-port? any/c any/c any)]
>         [(procedure-has-arity/c 4) (-> input-port? any/c any/c any/c any)]
>         [else (->* (input-port? any/c) #:rest list? any)])
>
> By the way it has to be procedure-has-arity/c, not
> procedure-includes-arity/c:
> (define (procedure-has-arity/c arity)
>   (define normalized-arity (normalize-arity arity))
>   (flat-named-contract
>    `(procedure-has-arity/c ,normalized-arity)
>    (λ (f)
>      (and (procedure? f)
>           (arity=? (procedure-arity f) normalized-arity)))))
>
> On Jun 29, 2014, at 8:00 AM, Roman Klochkov <kalimehtar at mail.ru> wrote:
>
> How to make a contract, that accepts
> (-> input-port? any/c any)
> (-> input-port? any/c any/c any)
> (-> input-port? any/c any/c any/c any)
> ...
> and
> (->* (input-port? any/c) #:rest list? any)
>
>
> So theare should be at least two args and first arg should be input-port.
>
> --
> Roman Klochkov
>
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