[racket] Why does (case ...) quote its matching value expressions?

From: Eli Barzilay (eli at barzilay.org)
Date: Sun Dec 28 18:47:23 EST 2014

On Wed, Dec 24, 2014 at 10:19 AM, J Arcane <jarcane at gmail.com> wrote:
> That is a lot more brief than mine. I just adapted a naive, unquoted version
> from the Racket case:

(The main point was that you can do compile-time computations, so it's a very
different thing...)

          ((lambda (x) (x x)) (lambda (x) (x x)))          Eli Barzilay:
                    http://barzilay.org/                   Maze is Life!

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