[racket] requiring modules in a namespace

In some cases I want a namespace that includes more than racket/base only,
preferably a namespace that includes all of module racket. For example, a
base-namespace does not include procedure force (as clearly documented) I
see two methods to require all of racket into a base-namespace (I imagine
there are more methods)
 
Method 1:
 
#lang racket
 
(define namespace-1
 (parameterize ((current-namespace (make-base-namespace)))
  (namespace-require 'racket)
  (current-namespace)))
 
(eval 'force namespace-1) ; -> #<procedure:force>
 
Method 2:
 
#lang racket
 
(define namespace-2
 (let ((namespace (make-base-namespace)))
  (eval '(require racket) namespace)
  namespace))
 
(eval 'force namespace-2) ; -> #<procedure:force>
 
I have also seen that nowadays even the following is accepted:
 
(eval '(define list 1) (make-base-namespace))
 
IIRC this was not accepted in earlier versions.
The above is in DrRacket's definitions window version
5.3.1.10--2012-12-21(8d5a069/a) [3m]. 
 
Questions:
What is preferable? (e.g. method 1 does not require procedure eval)
Do the methods work under all circumstances?
Possibly there are differences and pitfalls I have not noticed? 
 
My questions stems from the fact that even after many years, I am still
playing with my own interpreters (meta-recursive and correctly treating tail
positions). It is handy to have a namespace that provides all primitives I
need/want. Taking the whole as a namespace is fast and easy, especially when
testing meta-recursivity. Mods shaddow the namespace or I simply use
namespace-set-variable-value!
 
Thanks, Jos
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