[racket] `provide` failed under `#lang racket/load`
On Sun, Aug 4, 2013 at 10:40 AM, Carl Eastlund <cce at ccs.neu.edu> wrote:
> On Sun, Aug 4, 2013 at 4:32 AM, Yi Dai <plmday at gmail.com> wrote:
>
>>
>>
>>
>> On Sun, Aug 4, 2013 at 10:20 AM, Carl Eastlund <cce at ccs.neu.edu> wrote:
>>
>>> Yi,
>>>
>>> Most #lang languages implicitly create a module from the contents of the
>>> file. #lang racket/load, on the other hand, runs the contents of the file
>>> as top-level terms outside of any module. The provide form is not legal at
>>> the top level, as it is meaningless -- there's no module to provide things
>>> from. You need to either switch back to #lang racket or remove the
>>> provide, depending on what you're trying to accomplish.
>>>
>>
>> Thanks for the answer, Karl. I also found the answer in the doc:
>> http://docs.racket-lang.org/reference/load-lang.html. But very
>> confusingly, the doc keeps saying "racket/load" module.
>>
>
> Yes, the file is technically a module. However, the code you write is not
> evaluated in the context of that module. It is instead evaluated in a
> dynamically-generated top-level context. It might be clearer if we look at
> the explicit module generated by the two #lang languages:
>
> #lang racket
> <code1>
> <code2>
> ...
>
> is equivalent to
>
> (module <filename> racket
> <code1>
> <code2>
> ...)
>
> However,
>
> #lang racket/load
> <code1>
> <code2>
> ...
>
> is (basically) equivalent to
>
> (module <filename> racket
> (eval (quote <code1>))
> (eval (quote <code2>))
> ...)
>
Ah, now it is clearer. Thanks a lot, Karl.
>
>
>>
>>
>>> On Sun, Aug 4, 2013 at 4:12 AM, Yi Dai <plmday at gmail.com> wrote:
>>>
>>>> Hi,
>>>>
>>>>
>>>> I have the following code in a file named `foo.rkt`:
>>>>
>>>> ```
>>>> #lang racket/load
>>>>
>>>> (provide foo)
>>>>
>>>> (define foo 'bar)
>>>> ```
>>>>
>>>> When trying to run the code, I got the following confusing error:
>>>>
>>>> > `provide`: not at module level in: `(provide foo)`
>>>>
>>>> What does this mean? Why `provide` is not at module level?
>>>> Use `#lang racket` instead does not pose this problem. I am
>>>> confused. Any idea?
>>>>
>>>>
>>>> Yours truly,
>>>>
>>>> Yi
>>>>
>>>> ____________________
>>>> Racket Users list:
>>>> http://lists.racket-lang.org/users
>>>>
>>>>
>>>
>>
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>>
>>
>
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