[racket] cube-all

I developed my code using a recursive analysis.
________________________________________
From: Marco Morazan [morazanm at gmail.com]
Sent: Thursday, October 04, 2012 1:40 PM
To: Ashley Fowler
Cc: users at racket-lang.org
Subject: Re: [racket] cube-all

Tell us how you developed your code and we might be able to tell you
where you went wrong.

On Thu, Oct 4, 2012 at 12:17 PM, Ashley Fowler
<afowler2 at broncos.uncfsu.edu> wrote:
> I need to write a function that takes a list and cubes the whole list, for
> instance, (cube-all '(3 4 2 5)) returns (27 64 8 125).
>
> So far I have the code below, but it is not working out like I want it to.
> Any advice or suggestions?
> (define cube-all
> (lambda (ls)
> (if (null? ls)
>      ls
> (cons(car ls)(cube-all (cdr ls))
>
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--

Cheers,

Marco

Have a´¨)
¸.·´¸.·*´¨) ¸.·*¨)
(¸.·´ (¸.·´ * wonderful day! :)