[racket] String manipulation without regex opinion
On 11/06/2012 02:59 PM, Grant Rettke wrote:
> Hi,
>
> Usually there are homework problems and stuff for tweaking strings but I
> was just playing around for the fun of it. I wondered what is the "best
> way" to do a couple of simple tasks but without regex. Here are two of
> them. They are not optimized I just wrote them in a way that seemed the
> simplest. What is a better way or different way?
>
> #lang racket
>
> (require rackunit)
>
> ;; string -> string
> ;; Removes vowels from the input
> (define remove-vowels
> (lambda (word)
> (let ((test (lambda (c) (not (member c (list #\a #\e #\i #\o #\u)))))
> (ls (string->list word)))
> (list->string (filter test ls)))))
Here's one alternative that should allocate half as many intermediate
pairs (by switching from string->list and filter to in-string and #:unless):
(define (remove-vowels s)
(list->string
(for/list ([c (in-string s)]
#:unless (memv c '(#\a #\e #\i #\o #\u)))
c)))
If I were really worried about performance, I would allocate a new
string the size of the old string and copy characters from old to new,
skipping vowels, and take the appropriate substring at the end. I might
also delay the allocation of the copy until I found the first vowel; if
there are no values, then the function can just return the string itself
(unless the function needs to return a fresh string because of mutation
elsewhere in the program).
> (check-equal? (remove-vowels "") "")
> (check-equal? (remove-vowels "f") "f")
> (check-equal? (remove-vowels "a e i o u") " ")
>
> ;; string -> string
> ;; Replaces spaces in the input with dashes
> (define replace-spaces
> (lambda (word)
> (let ((test (lambda (c) (if (equal? c #\space) #\- c)))
> (ls (string->list word)))
> (list->string (map test ls)))))
>
> (check-equal? (replace-spaces "") "")
> (check-equal? (replace-spaces " ") "-")
> (check-equal? (replace-spaces "a b c") "a-b-c")
Similar, except here you wouldn't have to worry about resizing the copy
at the end.
Ryan