[racket] Some struct questions

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On 15-07-12 17:40, Harry Spier wrote:
> 1) In section 8 of the Racket reference there is this example: 
> ------------------------------------------- Examples: 
> (define-struct tree (val left right))
> 
>> (match (make-tree 0 (make-tree 1 #f #f) #f)
> [(tree a (tree b  _ _) _) (list a b)])
> 
> '(0 1) ----------------------------------
> 
> but I wasn't able to find any reference in the documentation to a
> constructor form make-struct-id .  I'm assuming that in the above
> example (match (make-tree 0 (make-tree 1 #f #f) #f) is equivalent
> to (match (tree 0 (tree 1 #f #f) #f)
> 
> Is that correct? Is make-struct-id  a deprecated form of the
> constructor procedure struct-id?

I believe define-struct is the deprecated struct-defining form
creating a "make-"-prefixed constructor and the new way is `struct'
which creates constructors with the name of the struct.

Marijn


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