[racket] Bouncing default value

On Tue, Feb 14, 2012 at 17:45, Chongkai Zhu <czhu at cs.utah.edu> wrote:

> I simply use
>
> (define (bar . x)
>  (apply foo 5 x))
>

Yes, but that does not work if the specified optional argument is not the
first one (and not the last one).
That works if all default arguments are all keyword-based though (using
keyword-apply).

Laurent
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