[racket] Accessing lambda arguments in a macro

Yes, I was thinking of naming the register explicitly too. 

On Sep 16, 2011, at 4:17 PM, Daniel MacDougall wrote:

> I suppose that would work. Sam suggested on #racket that I include the name of the argument in the macro definition:
> 
> (define-syntax-rule (foo bar form ...)
>   ((lambda (bar) form ...) "ARG"))
> 
> Then you could say:
> 
> (foo bar
>   ; Do stuff with bar here...
>   )
> 
> On Fri, Sep 16, 2011 at 1:12 PM, Matthias Felleisen <matthias at ccs.neu.edu> wrote:
> 
> 
> Why not just store the arguments to lambda in some 'register' and ask for them?
> 
> 
> 
> 
> On Sep 16, 2011, at 4:09 PM, Daniel MacDougall wrote:
> 
> > In this example it should return "ARG".
> >
> > On Fri, Sep 16, 2011 at 1:08 PM, Matthias Felleisen <matthias at ccs.neu.edu> wrote:
> >
> >
> > What should (foo bar) return?
> >
> >
> > On Sep 16, 2011, at 3:46 PM, Daniel MacDougall wrote:
> >
> > > Is there any way to define a macro that expands out to a lambda, and then access the arguments passed to that lambda from outside the macro in the calling context?
> > > Here's an example of what I mean:
> > >
> > > #lang racket
> > >
> > > (define-syntax-rule (foo form ...)
> > >   ((lambda (bar) form ...) "ARG"))
> > >
> > > (foo "Hello") ; => returns "Hello"
> > >
> > > (foo bar)     ; => expand: unbound identifier in module in: bar
> > >
> > >
> > > I'd like access to the "bar" argument on the last line. Is this possible with Racket macros?
> > >
> > > Thanks,
> > > Daniel
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> >
> >
> 
>