[racket] Accessing lambda arguments in a macro

In this example it should return "ARG".

On Fri, Sep 16, 2011 at 1:08 PM, Matthias Felleisen <matthias at ccs.neu.edu>wrote:

>
>
> What should (foo bar) return?
>
>
> On Sep 16, 2011, at 3:46 PM, Daniel MacDougall wrote:
>
> > Is there any way to define a macro that expands out to a lambda, and then
> access the arguments passed to that lambda from outside the macro in the
> calling context?
> > Here's an example of what I mean:
> >
> > #lang racket
> >
> > (define-syntax-rule (foo form ...)
> >   ((lambda (bar) form ...) "ARG"))
> >
> > (foo "Hello") ; => returns "Hello"
> >
> > (foo bar)     ; => expand: unbound identifier in module in: bar
> >
> >
> > I'd like access to the "bar" argument on the last line. Is this possible
> with Racket macros?
> >
> > Thanks,
> > Daniel
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>
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