[racket] macro expansion function in Scheme

From: Matthias Felleisen (matthias at ccs.neu.edu)
Date: Tue Jul 12 10:35:49 EDT 2011

	
Since Ryan's stepper does that and renders the expression for you, I suspect he could supply something close to syntax->datum*. 




On Jul 12, 2011, at 10:30 AM, Bas Steunebrink wrote:

> Thanks Matthias and Eli, I understand what expand does and that syntax->datum throws away too much (by design). Still my question remains of how to obtain a datum that is equivalent to a given quoted expression (when eval'ed) but with all macros expanded (generating fresh symbols where necessary). So does there exist a function syntax->datum* such that:
> 
> > (define-syntax m
>    (syntax-rules ()
>      ((_ x)
>       (lambda (x) (lambda (y) x)))))
> > (((m y) #t) #f)
> #t   ; OK
> > (syntax->datum* (expand '(m y)))
> (lambda (y) (lambda (g42) y))   ; g42 is a fresh symbol
> > (((eval (syntax->datum* (expand '(m y)))) #t) #f)
> #t   ; using Racket's syntax->datum gives #f
> 
> Please note that I'm really interested in getting just the macro-expanded datum (otherwise I would've been done already!).
> 
> 
> Thanks again for your kind help,
> Bas
> 
> 
> 
> 
> On 7/12/11 16:17 PM, Matthias Felleisen wrote:
>> 
>> 
>> On Jul 12, 2011, at 10:16 AM, Eli Barzilay wrote:
>> 
>>> 8 minutes ago, Matthias Felleisen wrote:
>>>> 
>>>> The following experiment produces a bit more insight:
>>>> 
>>>>> (((eval (expand '(m y))) #t) #f)
>>>> #t
>>>> 
>>>> The result of expand compiles to the correct closure.
>>>> 
>>>> So the docs for syntax->datum are dead serious when they say that it
>>>> "returns a datum by stripping the lexical information, source
>>>> location information, properties, and tamper status from stx."
>>> 
>>> Try also the macro stepper.  From an upcoming package for the repl:
>>> 
>>>  ->  (define-syntax m
>>>       (syntax-rules ()
>>>         ((_ x)
>>>          (lambda (x) (lambda (y) x)))))
>>>  ->  ,stx (m y) *
>>>  syntax set
>>>  stepper:
>>>  Macro transformation
>>>  (m y)
>>>    ==>
>>>  (lambda:1 (y) (lambda:1 (y:1) y))
>>> 
>>> (But you'd usually want to use the gui version...)
>> 
>> Fire up drracket and run the stepper.




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