From: Dave Gurnell (d.j.gurnell at gmail.com) Date: Fri May 22 11:07:25 EDT 2009 |
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Hi all, Is there anything special about a mixin that distinguishes it from a regular procedure, apart from the fact that it operates on classes? In other words, if I compose two mixins like this: (define b<%> (interface ())) (define c<%> (interface ())) (define mixin-ab (mixin () (b<%>) (super-new))) (define mixin-bc (mixin (b<%>) (c<%>) (super-new))) (define mixin-ac (compose mixin-bc mixin-ab)) is mixin-ac actually a mixin? Cheers, -- Dave
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