[plt-scheme] Undefined identifier? hey... it's defined!

On Wed, 2009-06-24 at 14:13 -0400, Matthias Felleisen wrote:
> The rhs of definitions are evaluated in sequence. In foo2, you are  
> evaluating (bar) in a context where foo1 is bound and evaluated and  
> bar isn't. Nothing new.
> 
> Then again, in a module this kind of thing could go away.
> 
> 

You're right.. it does make sense... wierd I only stumbled at it now. 
I always thought that rhs of definitions were only evaluated in a
sequence outside of a module and inside it wouldn't make sense.

> 
> 
> On Jun 24, 2009, at 2:02 PM, Paulo J. Matos wrote:
> 
> > Hi all,
> >
> > When you think scheme hold no more strange surprises, you end up  
> > finding
> > something you can't explain. It's even worse when you understand the
> > error message but you have no idea why it's being thrown at you.
> >
> > So this is just small example showing the problem:
> > #lang scheme
> >
> > (define (foo1 x)
> >   (let ([y (bar x)])
> >     (+ y x)))
> >
> > (define foo2
> >   (let ([y (bar)])
> >     (lambda (x)
> >       (+ y x))))
> >
> > (define (bar (x 2))
> >   (* x x))
> >
> > I get in 4.2:
> > reference to an identifier before its definition: bar
> >
> > Why is bar undefined in foo2?
> >
> > Cheers,
> >
> > Paulo Matos
> >
> > _________________________________________________
> >   For list-related administrative tasks:
> >   http://list.cs.brown.edu/mailman/listinfo/plt-scheme
>