| From: Eli Barzilay (eli at barzilay.org) Date: Sat Mar 22 23:06:58 EDT 2008 | 
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On Mar 22, Doug Orleans wrote:
> 
> The thing that seems like voodoo to me in my version is that there's
> no mutation involved: [...]
But there is state -- in the for loop (whether one that gets mutated
or with a named let loop)...
-- 
          ((lambda (x) (x x)) (lambda (x) (x x)))          Eli Barzilay:
                  http://www.barzilay.org/                 Maze is Life!
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