From: Eli Barzilay (eli at barzilay.org) Date: Sat Mar 22 23:06:58 EDT 2008 |
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On Mar 22, Doug Orleans wrote: > > The thing that seems like voodoo to me in my version is that there's > no mutation involved: [...] But there is state -- in the for loop (whether one that gets mutated or with a named let loop)... -- ((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay: http://www.barzilay.org/ Maze is Life!
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