| From: Peter Horst (phorst at speakeasy.net) Date: Sat May 13 00:21:47 EDT 2006 |
|
OK, so I've got (under Dr. Scheme 3.01 "Textual"):
(define square
(lambda (n)
(* n n)))
(define hypotenuse
(lambda (adjacent opposite)
(sqrt (+ (square adjacent) (square opposite)))))
Calculating the hypotenuse of a 30-60-90 right triangle I get:
> (hypo (sqrt 3) 1)
2.0
but
> (square (sqrt 3))
2.9999999999999996
How come?
Thank you!
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