From: Bill Richter (richter at math.northwestern.edu) Date: Fri Apr 23 21:51:20 EDT 2004 |
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Joe Marshall <jrm at ccs.neu.edu> spanks me soundly: In the expression (foo goo) as normally understood, both foo and goo are variables and evaluating a variable does not cause side-effects. You're right, Joe! How silly of me! And you're right: if foo is bound to a procedure of no arguments, say by (define (foo) <body>) Then evaluating (foo) will evaluate the body, which might well contain side-effect stuff. So ((foo) (goo)) is the right expression to study.
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