[racket] Determining type from a syntax object

From: Matthias Felleisen (matthias at ccs.neu.edu)
Date: Mon Jun 16 06:54:59 EDT 2014

That's what I thought you wanted it for so my answer stands -- Matthias



On Jun 15, 2014, at 12:55 AM, Spencer Florence wrote:

> This is about making decisions at compile time. Specifically I have a sequence of expressions I want to partition into expressions of some type T and expressions of other types.
> 
> 
> On Sat, Jun 14, 2014 at 7:34 PM, Robby Findler <robby at eecs.northwestern.edu> wrote:
> Would it be enough to expand into an 'ann' expression? Or do you need
> to make decisions at compile time based on whether or not the types
> worked?
> 
> Robby
> 
> On Sat, Jun 14, 2014 at 2:04 PM, Matthias Felleisen
> <matthias at ccs.neu.edu> wrote:
> >
> > No, TR expands first, then checks. -- Matthias
> >
> >
> >
> >
> > On Jun 14, 2014, at 2:59 PM, Spencer Florence wrote:
> >
> >> Hey All,
> >>
> >> I'm trying to take advantage of typed/racket in a few macros. Is there any way to check the type of an expression from its syntax object? something like:
> >>
> >> (:has-type? (-> Void) #'expression)
> >>
> >>
> >> --Spencer
> >> ____________________
> >>  Racket Users list:
> >>  http://lists.racket-lang.org/users
> >
> >
> > ____________________
> >   Racket Users list:
> >   http://lists.racket-lang.org/users
> 

-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.racket-lang.org/users/archive/attachments/20140616/c5b44359/attachment-0001.html>

Posted on the users mailing list.