[racket] Cube two numbers

From: Ashley Fowler (afowler2 at broncos.uncfsu.edu)
Date: Fri Sep 14 19:26:31 EDT 2012

I have to make this code called cube-two where it takes two numbers and cubes the both of them .

This is what I have so far:

(define cube-two(lambda(X Y)(list'(* X X X)(* Y Y Y))

but the problem is, is that it only executes Y like the example below...

> (cube-two 3 4)
((* x x x) 64)

How would I make it so it will execute both numbers?

For instance

>(cube-two 3 4)
(27 64)
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