# [racket] Racket Question

On Friday, March 30, 2012, Brandon T wrote:
>* Hi i have a question that i could not find an answer to on your site, not
*>* could i find an answer on stack overload. By default, racket prints the
*>* first 25 digits of a irrational fraction. i.e.
*>*
*>* >1/998
*>* 0.0010020040080160320641282...
*>*
*>*
*Just to point out that 1/998 is not irrational. It has a finite decimal
representation. See:
http://en.wikipedia.org/wiki/Repeating_decimal
We can can compute the repeating decimal representation of a fraction by
repeated division on the remainders, and since there are only a finite
number of distinct remainders of 998, we're guaranteed to terminate at some
point, or find a loop.
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