[racket] Multiplying by 0

I understand. However, not only that disregards type promotion but also 
is incoherent since (+ 0 0.0) evaluates to 0.0.

On 13-02-2011 16:17, Robby Findler wrote:
> I believe one of the rules is that multiplying exact 0 by any number
> gives you back exact 0.
>
> Robby
>
> 2011/2/13 José Lopes<jose.lopes at ist.utl.pt>:
>> Shouldn't (* 0.0 0) evaluate to 0.0?
>>
>> --
>> José António Branquinho de Oliveira Lopes
>> 58612 - MEIC-A
>> jose.lopes at ist.utl.pt
>>
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-- 
José António Branquinho de Oliveira Lopes
58612 - MEIC-A
jose.lopes at ist.utl.pt