[racket] Super basic question about strings

From: Matthias Felleisen (matthias at ccs.neu.edu)
Date: Wed Nov 17 09:13:12 EST 2010

On Nov 17, 2010, at 2:40 AM, Eli Barzilay wrote:

>   (define (alist->string alist)
>      (string-join
>       (for/list ([a (in-list alist)])
>         (format "~a=~a" (car a) (cdr a)))
>       " "))

Somewhat more 'native': 

(define (alist->string l) 
    (map (lambda (x) (format "~s=~s" (car x) (cdr x))) l) " "))

in the sense that map preceded our for/ loops by 4 decades. 

-- Matthias

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