# [plt-scheme] Typed Scheme: type of filter ?

The type of `filter' in the initial environment was incorrectly given
as the simple version. This has now been fixed in SVN.
Thanks,
sam th
On Thu, Jun 19, 2008 at 2:59 AM, Michel Salim <michel.sylvan at gmail.com> wrote:
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*>* In the POPL 08 paper, the type of filter is given as
*>*
*>* (All (a b) ((a --b--> Boolean) (listof a) -> (Listof b))
*>*
*>* which would allow one to do things like
*>*
*>* (map add1 (filter number? '(1 #t 2 #f 3))
*>*
*>* in fact, Sam gave this example on Lambda the Ultimate
*>*
*>* In the released version of PLT Scheme 4.0, however, this is the type
*>* of filter:
*>* (All (a) ((<a> -> Boolean) (Listof <a>) -> (Listof <a>)))
*>*
*>* which means the above failed. As can be verified:
*>*
*>* (filter number? '(1 #t #f))
*>* - - : (Listof (U Integer #f #t))
*>* (1)
*>*
*>* The handling of booleans also strikes me as a bit odd.
*>*
*>>* > (define: bools : (Listof Boolean) '(#t #f))
*>>* > bools
*>* - - : (Listof Boolean)
*>* (#t #f)
*>>* > (define bools2 bools)
*>>* > bools2
*>* - - : (Listof Boolean)
*>* (#t #f)
*>>* > (define bools3 '(#t #f))
*>>* > bools3
*>* - - : (List #t #f)
*>* (#t #f)
*>*
*>* A similar behavior is exhibited for lists of numbers: '(1 1.5 2) :
*>* (List Integer Number Integer), so heterogenous lists are treated just
*>* like tuples in Haskell or ML, but is there any reason #t and #f are
*>* not treated as just instances of Boolean ?
*>*
*>* Thanks,
*>*
*>* - --
*>* Michel Salim
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--
sam th
samth at ccs.neu.edu