From: Peter Horst (phorst at speakeasy.net) Date: Sat May 13 00:21:47 EDT 2006 

OK, so I've got (under Dr. Scheme 3.01 "Textual"): (define square (lambda (n) (* n n))) (define hypotenuse (lambda (adjacent opposite) (sqrt (+ (square adjacent) (square opposite))))) Calculating the hypotenuse of a 306090 right triangle I get: > (hypo (sqrt 3) 1) 2.0 but > (square (sqrt 3)) 2.9999999999999996 How come? Thank you!
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